0.6x^2+6x-9.6=0

Solution for 0.6x^2+6x-9.6=0 equation:

0.6x^2+6x-9.6=0

a = 0.6; b = 6; c = -9.6;
Δ = b2-4ac
Δ = 62-4·0.6·(-9.6)
Δ = 59.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{59.04}}{2*0.6}=\frac{-6-\sqrt{59.04}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{59.04}}{2*0.6}=\frac{-6+\sqrt{59.04}}{1.2}
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